SOLUTION: A submarine let Hawaii two hours before an aircraft carrier. The vessels traveled in opposite directions. The aircraft carrier traveled at 25 mph for nine hours. After this time th

Question 411334: A submarine let Hawaii two hours before an aircraft carrier. The vessels traveled in opposite directions. The aircraft carrier traveled at 25 mph for nine hours. After this time the vessels were 280 miles apart. Find the submarines speed.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

D = r*t

Let x represent the submarines speed.

Question states*** 280mi apart after traveling opposite directions

 11hr*x + 25mph*9hr =  280mi   |note:submarine left Hawaii two hours before an aircraft carrier

Solving for x

    11hrx = 55mi

      x = 5mph, the submarine's speed



CHECKING our Answer***

 55mi + 225mi = 280mi 

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