# SOLUTION: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 92 slower than the other. If the two jets are 10,602 apart after 9 hours, what is the

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 Click here to see ALL problems on Travel Word Problems Question 411244: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 92 slower than the other. If the two jets are 10,602 apart after 9 hours, what is the rate of each jet? Found 2 solutions by ewatrrr, rfadrogane:Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! Hi Let x and (x-92)represent the rates each of the jets are traveling Question states*** D= r*t 9x + 9(x-92) = 10,602mi Solving for x 18x = 10602+ 825 18x = 11430 x = 635mph. The other jet traveling at 543mph. (635-92) CHECKING our Answer*** 9hr*635mph + 9hr*543mph = 10,602mi Answer by rfadrogane(214)   (Show Source): You can put this solution on YOUR website!Two jets leave an air base at the same time and travel in opposite directions. One jet travels 92 slower than the other. If the two jets are 10,602 apart after 9 hours, what is the rate of each jet? Sol'n: note: your lacking of units... St=S1+S2 10,602=9v+9(v-92) 10,602=18v-828 18v=10,602+828 18v=11,430 v=635 v-92=543 thus the rate are 635 & 543 ----answer ^_^