SOLUTION: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 92 slower than the other. If the two jets are 10,602 apart after 9 hours, what is the

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Question 411244: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 92 slower than the other. If the two jets are 10,602 apart after 9 hours, what is the rate of each jet?
Found 2 solutions by ewatrrr, rfadrogane:
Answer by ewatrrr(10682) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x and (x-92)represent the rates each of the jets are traveling

Question states*** D= r*t

   9x + 9(x-92) = 10,602mi

Solving for x

        18x = 10602+ 825

        18x = 11430

          x = 635mph.  The other jet traveling at 543mph.  (635-92)



CHECKING our Answer***

  9hr*635mph + 9hr*543mph = 10,602mi

Answer by rfadrogane(214) About Me  (Show Source):
You can put this solution on YOUR website!
Two jets leave an air base at the same time and travel in opposite directions. One jet travels 92 slower than the other. If the two jets are 10,602 apart after 9 hours, what is the rate of each jet?
Sol'n:
note: your lacking of units...
St=S1+S2
10,602=9v+9(v-92)
10,602=18v-828
18v=10,602+828
18v=11,430
v=635
v-92=543

thus the rate are 635 & 543 ----answer
^_^