SOLUTION: A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph. One hour later, his support staff leaves the base in a car going 30 mph in the same directio
Algebra.Com
Question 407702: A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph. One hour later, his support staff leaves the base in a car going 30 mph in the same direction. How long will it take the support staff to catch up with the cyclist once the car leaves the base?
I just wanna fid out how to set it up cause I know the formula(r*t=d)
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
t is the time to catch up
the cyclist's time is t plus his one hr head start
they catch up when the staff has traveled the same (equal) distance as the cyclist
16 * (t + 1) = 30 * (t)
RELATED QUESTIONS
A cyclist leaves his training base for a morning workout, riding at the rate of 20 mph.... (answered by mananth)
A cyclist leaves his training base for a morning workout, riding at the rate of 20 mph.... (answered by mananth)
A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph.... (answered by checkley79)
A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph.... (answered by ikleyn,josgarithmetic)
A cyclist leaves his training base for a morning workout, riding at the rate of 10 mph.... (answered by stanbon)
i cant figure out how to correctly form an equation for this:
a cyclist leaves his... (answered by nerdybill,stanbon)
A cyclist leaves Las Vegas riding at the rate of 18 mph. One hour later, a car leaves Las (answered by ankor@dixie-net.com)
An amateur cyclist is training for a road race. He rode the first 27-mile portion of his... (answered by Boreal)
A cyclist training for a distance race starts on a training ride at 7:00am trying to... (answered by stanbon)