SOLUTION: Suppose that you have entered a 90-mile biathlon that consists of a run and bicycle race. During your run, your average rate is 7 mph and during your bicycle race, your average rat

Question 406329: Suppose that you have entered a 90-mile biathlon that consists of a run and bicycle race. During your run, your average rate is 7 mph and during your bicycle race, your average rate is 26 mph. You finish the race in 5 hours. What is the distance of the run and what is the distance of the bicycle race? Round your answer to the nearest tenth of a mile.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose that you have entered a 90-mile biathlon that consists of a run and bicycle race. During your run, your average rate is 7 mph and during your bicycle race, your average rate is 26 mph. You finish the race in 5 hours. What is the distance of the run and what is the distance of the bicycle race? Round your answer to the nearest tenth of a mile.
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Run DATA:
rate = 7 mph; time = x hrs ; distance = 7x miles
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Bike DATA:
rate = 26 mph; time = 5-x hrs ; distance = 26(5-x) miles
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Equation:
distance + distance = 90 miles
7x + 26*5 - 26x = 90
-19x = -40
x = 40/19 hrs
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7x = 280/19 = 14.73 miles of running
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90-14.73 = 75.26 miles of biking.
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Cheers,
Stan H.
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