# SOLUTION: A tractor travels 10 miles in the same amount of time it takes a car to travel 15 miles. The rate of the tractor is 15 mph less than the rate of the car. Find the rate of the tra

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: A tractor travels 10 miles in the same amount of time it takes a car to travel 15 miles. The rate of the tractor is 15 mph less than the rate of the car. Find the rate of the tra      Log On

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 Click here to see ALL problems on Travel Word Problems Question 403223: A tractor travels 10 miles in the same amount of time it takes a car to travel 15 miles. The rate of the tractor is 15 mph less than the rate of the car. Find the rate of the tractor. Answer by rvquartz(19)   (Show Source): You can put this solution on YOUR website!three key relationships for any vehicle in this case are: (a) distance = (speed)(time) (b) speed = distance /time (c) time = distance /speed for the car: distance = d = 15 miles speed = v time = t for the tractor: distance = D = 10 miles speed = v - 15 time = T tractor time = car time, so T = t and using key relationship (c), we have: 10/(v-15) = 15/v we can keep the equivalence if we multiply each side by the product of the denominators 10v = 15(v-15) that is the same as 10v = 15v - 225 solving for v: -5v = -225 5v = 225 v = 225/5 v = 45 miles per hour V = v - 15 = 30 miles per hour the rate of the tractor is 30 miles per hour