SOLUTION: Here is another one I would need help with: Kevin was swimming agains the current, it took him 8 min. to swim 200 meters. Swimming back with the current took half as long. What is

Question 403213: Here is another one I would need help with:
Kevin was swimming agains the current, it took him 8 min. to swim 200 meters. Swimming back with the current took half as long. What is his average swimming speed and the speed of the current?
Thank you for your help
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = rate of swimming without current
Let = rate of current
= rate of swimming against current
= rate of swimming with current
------------------
given:
(1) meters
(2) meters
------------------
This is 2 equations and 2 unknowns, so it's solvable
(1)
(2)
Multiply both sides of (2) by
and add the equations
(1)
(2)

and, from (2),
(2)

-----------------
Always use the definition (ave. speed) = (total distance)/(total time)
His ave. speed =
m/min
The speed of the current is 12.5 m/min

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