SOLUTION: A golf ball is launched upward with an initial speed of 30 m/sec by a golfer atop the Washington Monument, which is 160 m above the ground. How high above the ground will the ball

Question 402443: A golf ball is launched upward with an initial speed of 30 m/sec by a golfer atop the Washington Monument, which is 160 m above the ground. How high above the ground will the ball be after 3 sec?
I'm not sure how to set this up. Should I use: distance = rate � time?

Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Distance = rate*time only works for constant velocity problems. In this problem, we have the acceleration due to gravity.

The formula for determining position given a constant acceleration is , where a = -9.81 m/s^2, is the original velocity, is the original position (this equation is derived using integral calculus). Here, t = 3 s, = 30 m/s, = 160 m. Therefore,

= 205.9 meters
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