SOLUTION: Two cyclists, 60 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of t

Question 400837: Two cyclists, 60 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
Found 2 solutions by rfer, josmiceli:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
x+2x=30
3x=30
x=10 mph
2x=20 mph
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
you can think of 1 standing still and the
other moving at the sum of their speeds

mi/hr
mi/hr
The speed of the faster cyclist was 20 mi/hr
check answer:
slower cyclist:

mi
faster cyclist:

mi

OK
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