SOLUTION: Two bikers leave 3 hours apart. The first is traveling at 6 mph and the second at 10 mph. How long until the second biker catches up with the first biker?
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Question 397606: Two bikers leave 3 hours apart. The first is traveling at 6 mph and the second at 10 mph. How long until the second biker catches up with the first biker?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let x = # hours before the 2nd biker catches up
==> x + 3 = # hours of travel of 1st biker when 2nd biker catches up
Then 6(x+3) = 10x
==> 6x + 18 = 10x
==> 18 = 4x
==> x = 4.5 hours.
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