SOLUTION: if h=0 what is the answer to h=-16t^2+625

Algebra.Com
Question 397361: if h=0 what is the answer to h=-16t^2+625
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
if h=0 what is the answer to h=-16t^2+625
-16t^2 + 625 = 0 |multiplying thru by -1
16t^2 - 625 = 0
16t^2 = 625
t^2 = 625/16
t = ± 25/4
RELATED QUESTIONS

h(t)=80t-16t^2, 0 (answered by jim_thompson5910)
Hello, I wanted to see if I was doing this problem correctly. I started the answer... (answered by nerdybill)
H= -16t^2 + 48. What is the height at 0 seconds (answered by Alan3354)
h(t)=-16t^2+vt+h if initial velocity is 64ft/s what is the max... (answered by Alan3354)
which is the standard to... (answered by stanbon)
If given the equation: {{{h=(-16t^2)+560t}}}, when does h become... (answered by rchill)
I have this problem that I would like someone to check my work: If a skydiver jumps... (answered by venugopalramana)
a rock falls from a tower that is 320 feet high. As it is falling, its height is given... (answered by Alan3354)
What is the velocity if H = 64t - 16t ^ 2? How can i solve for H? How can i solve for... (answered by KMST)