SOLUTION: A lawn care company wants to mix a 20% fertilizer solution with 15 liters of a 50% fertilizer solution. How much of the 20% solution is needed to get a mixture containing 30% ferti

SOLUTION: A lawn care company wants to mix a 20% fertilizer solution with 15 liters of a 50% fertilizer solution. How much of the 20% solution is needed to get a mixture containing 30% ferti

Algebra.Com

Question 394918: A lawn care company wants to mix a 20% fertilizer solution with 15 liters of a 50% fertilizer solution. How much of the 20% solution is needed to get a mixture containing 30% fertilizer?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
0.20x + 0.5 * 15 = 0.30(x +15)
==> 0.20x + 7.5 = 0.30x + 4.5
==> 3 = 0.10x
==> x = 30 liters of the 20% solution must be added.
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