SOLUTION: Two pipes simultaneously function to fill a tank in 12 hours.If one pipe takes 10 hours less than the other ,find the time taken by the two pipes.

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Question 38863: Two pipes simultaneously function to fill a tank in 12 hours.If one pipe takes 10 hours less than the other ,find the time taken by the two pipes.
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
One pipe = x-10 hours
Another pipe = x hours
Equation:
1%2Fx%2B1%2F%28x-10%29=1%2F12
[(x)+(x-10)]=[(x)(x-10)]/12
2x-10=%28x%5E2-10x%29%2F12
24x-120=x%5E2-10x
x%5E2-34x%2B120=0
solve that you get x=4 or x=30
Neglect x=4
30-10=20
Hence, one pipe can fill the tank is 30 hours and another can fill it in 20 hours.
Paul.