SOLUTION: Two pipes simultaneously function to fill a tank in 12 hours.If one pipe takes 10 hours less than the other ,find the time taken by the two pipes.

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One pipe = x-10 hours
Another pipe = x hours
Equation:

[(x)+(x-10)]=[(x)(x-10)]/12



solve that you get x=4 or x=30
Neglect x=4
30-10=20
Hence, one pipe can fill the tank is 30 hours and another can fill it in 20 hours.
Paul.