SOLUTION: A speedboat takes 4 hours longer to go 80 miles up a river than to return. If the boat cruises at 15 miles per hour in still water, what is the rate of the current?

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Question 388013: A speedboat takes 4 hours longer to go 80 miles up a river than to return. If the boat cruises at 15 miles per hour in still water, what is the rate of the current?
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Start with the basic formula, Distance equals Rate times Time.



But express it as time as a function of distance and rate:



So let's talk about the downstream trip first. Going downstream the boat goes 15 mph PLUS the rate of the current, i.e. , and the 80 mile trip is accomplished in hours, so:



Now let's look at the upstream trip. This time the boat speed relative to the shore is 15 mph MINUS the rate of the current, , and the 80 mile trip is accomplished in hours, so:



A little algebra and fraction addition:





Ah ha! Now we have two things both equal to , so:



Cross-multiply, collect like terms, and put the quadratic into Standard Form.



Factor and solve. Discard the negative root -- unless you can find a river that flows upstream.


John

My calculator said it, I believe it, that settles it
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