SOLUTION: train a and b are traveling the same direction on parallel tracks. Train a is traveling at a rate of 100mph and train b at 125mph. Train a passes a station at 6:10am and train b pa

Question 387964: train a and b are traveling the same direction on parallel tracks. Train a is traveling at a rate of 100mph and train b at 125mph. Train a passes a station at 6:10am and train b passes the same station at 6;22am what time will train b catch up to train a?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
train A has a 12 min (6:22 - 6:10) head start , or 1/5 hr (12 / 60)

at 100 mph , 1/5 hr means a 20 mi head start (100 mph * 1/5 hr)

train B is catching up at 25 mph (125 mph - 100 mph)

it takes train B 4/5 hr to catch up (20 mi / 25 mph) , this is 48 min (4/5 * 60)

so B catches A at 7:10 (6:22 + 0:48)
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