SOLUTION: A ball is thrown upward with an initial speed of 24.5 m/s. When is it 19.6m high?
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Question 387938: A ball is thrown upward with an initial speed of 24.5 m/s. When is it 19.6m high?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
You didn't specify the equation of motion, or the starting height.
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h(t) = -4.9t^2 + vt is commonly used, assuming h(0) = 0
h(t) = -4.9t^2 + 24.5t
-4.9t^2 + 24.5t = 19.6
t^2 - 5t + 4 = 0
(t-1)*(t-4) = 0
t = 1 second going up
t = 4 seconds descending
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