SOLUTION: If bus A arrives every 27 minutes and bus B arrives every 15 minutes, and both buses arrive at a stop at 5:07am, what time will they arrive at the same time again?

Question 387271: If bus A arrives every 27 minutes and bus B arrives every 15 minutes, and both buses arrive at a stop at 5:07am, what time will they arrive at the same time again?
Found 3 solutions by edjones, stanbon, richwmiller:
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
27*15=405
405/3=135 they are both (27 and 15) divisible by 3.
135/27=5
135/15=9
.
135/60=9/4=1:45
5:07 + 1:45 = 6:52 AM The next time that they will arrive together.
.
Ed
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
If bus A arrives every 27 minutes and bus B arrives every 15 minutes, and both buses arrive at a stop at 5:07am, what time will they arrive at the same time again?
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Find the least common multiple of 15 and 27.
15 = 3*5
27 = 3^3
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lcm = 3^3*5 = 27*5 = 135 minutes
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5:07 + 135 min = 5:07+ (2hrs 15min) = 7:22 am
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Cheers,
Stan H.

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
27=3*9
15=3*5
3*9*5=135
they will arrive together in 135 minutes
135 minutes =2:15 minutes
5:07+2:15:7:22 am
They will arrive again at 7:22 am

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