SOLUTION: A jogger who can run an 8-minute mile starts half mile ahead of a jogger who can run a 6-minute mile. How long will it take the faster jogger to catch the slower jogger?
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Question 386528: A jogger who can run an 8-minute mile starts half mile ahead of a jogger who can run a 6-minute mile. How long will it take the faster jogger to catch the slower jogger?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
d = r * t
t * (1/8) = [t * (1/6)] + 1/2
multiplying by 24 ___ 3t = 4t + 12
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