SOLUTION: Two cyclists, 120 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of
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Question 383311: Two cyclists, 120 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let x = rate of one cyclist. Then 2x = rate of other cyclist.
Then by using the distance formula on each cyclist,
4x + 4*(2x) = 120;
4x + 8x = 120;
12x = 120;
x = 10 miles per hour, the rate of one cyclist, and
20 miles per hour, the rate of the other cyclist.
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