Hi,

Let x represent speed of  slower car and (x +40mph) the speed of the faster

D = r*t  OR D/r = t  Times being the same, sets up the equality:



cross multiplying to solve for x

350x = 150(x + 40)

350x = 150x + 40*150

200x = 40*150

x = 40*150/200  = 6000/200

x =30kmph, the speed of  slower car 

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
 The working equation is always distance = rate x time, or d = rt.

If the cars travel for the same time t, and we call the speed of the slower car r, the faster car travels at a speed of r+40.

So 

150=rt

350=(r+40)t

Let us solve the first one for t and substitute it into the second, thus solving for r, the speed of the slower car.  So...

t = 150/r

and









 km/hr 

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