# SOLUTION: Jan can run 7.5 meters per second, Mary at 8.0 meters per second. On a race track Jan is given a 25 meter head start, the race ends in a tie. How long is the track?

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 Question 375190: Jan can run 7.5 meters per second, Mary at 8.0 meters per second. On a race track Jan is given a 25 meter head start, the race ends in a tie. How long is the track?Found 2 solutions by mananth, corncob:Answer by mananth(12269)   (Show Source): You can put this solution on YOUR website!Jan can run 7.5 meters per second, Mary at 8.0 meters per second. On a race track Jan is given a 25 meter head start, the race ends in a tie. How long is the track? Jan 7.5 m/s Mary 8m/s .. let the track distance = x Jan gets 25 m head start .. Time taken is the same .. time = d/r (x-25)/7.5 = x/8 (x-25)*8=7.5x 8x-200=7.5x 8x-7.5x=200 0.5x=200 x=200/0.5 x=400 meters the track length ... m.ananth@hotmail.ca Answer by corncob(8)   (Show Source): You can put this solution on YOUR website!Here you see two variables...Jan who can run 7.5 meters per second and Mary who can run 8 meters a second. To figure out how long the trck is, if they tie, you will need to assign variables to help make the problem easier. A good universal varibale to use is x. In turn, you goal is to try to find out what x is. So assigning variables: I would make Jan's 7.5 plus a head start into: 7.5x+25 Jan's wold be: 8x distance of the track is:x Then you set up an equation that would make then equil each other, because they tie. A sample of the equation could be: 7.5x+25=8x From there you will simplify the problem by getting all of the x's to one side. 7.5x+25-7.5x=8x-7.5x YOu do it like this because when solving an equation, you have to do to each side the same thing... then you have, 25=.5x That is not finished because .5 is not what we are looking for, so you multiply 0.5x times 2 to get 1x 25*2=.5x*2 50=x So the answer is 50 meters!