SOLUTION: Blaise rode his bike to his friend Elroy's house, which was 15 miles away. After he had been riding for half an hour, he go a flat tire. He walked his bike the rest of the way. The

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Question 374395: Blaise rode his bike to his friend Elroy's house, which was 15 miles away. After he had been riding for half an hour, he go a flat tire. He walked his bike the rest of the way. The total trip took him 3 hours. If his walking rate was one-fourth as fast as his riding rate, how fast did he ride?
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Blaise rode his bike to his friend Elroy's house, which was 15 miles away.
After he had been riding for half an hour, he go a flat tire.
He walked his bike the rest of the way. The total trip took him 3 hours.
If his walking rate was one-fourth as fast as his riding rate, how fast did he ride?
:
Let w = his walking rate
then
4w = his riding rate
:
Given that he rode .5 hrs, then he walked: 3 - .5 = 2.5 hrs
:
Write a distance equation: Dist = time * speed
2.5w + .5(4w) = 15
:
2.5w + 2w = 15
:
4.5w = 15
w = 15%2F4.5
w = 31%2F3 mph is his walking speed
then
4(31%2F3) = 131%2F3 mph is his riding speed
:
:
Check solution using decimals
2.5(3.33) + .5(13.33) = 14.99 ~ 15, confirms our solutions