SOLUTION: Flying with the wind, a plane flew 960 mi in 4 h. Against the wind, the plane required 6 h to fly the same distance. Find the rate of the plane in calm air and the rate of the wind

SOLUTION: Flying with the wind, a plane flew 960 mi in 4 h. Against the wind, the plane required 6 h to fly the same distance. Find the rate of the plane in calm air and the rate of the wind

Algebra.Com

Question 371417: Flying with the wind, a plane flew 960 mi in 4 h. Against the wind, the plane required 6 h to fly the same distance. Find the rate of the plane in calm air and the rate of the wind.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The "rate in calm air" is the airspeed.
It's the average of the 2 groundspeeds.
The windspeed is the difference between airspeed and groundspeed.

RELATED QUESTIONS
Flying with the wind, a plane flew 960 mi in 3 h. Against the wind, the plane required 4... (answered by lwsshak3)

Flying with the wind, a plane flew 1500 mi in 5 h. Against the wind, the plane required 6 (answered by richwmiller)

Flying with the wind, a plane flew 1200 mi in 5 h. Against the wind, the plane required 6 (answered by ikleyn)

Flying with the wind, a plane flew 800 mi in 4 h. Against the wind, the plane required 8... (answered by Alan3354)

Flying with the wind, a plane flew 1200 mi in 4 h. Against the wind, the plane required 5 (answered by josgarithmetic)

A turboprop plane flying with the wind flew 960 mi in 3 h. Flying against the wind, the... (answered by mananth)

Flying with the wind, a plane flew 1,120 mi in 4 h. Against the wind, the plane required... (answered by mananth,MathTherapy)

Flying with the wind, a plane flew 1200 mi in 4h. Against the wind, the plane required 5h (answered by josgarithmetic)

A plane traveling with the wind flew 2185 mi in 4.75 h. Against the wind, the plane... (answered by josgarithmetic)