SOLUTION: A consultant traveled 7 hours to attend a meeting. The return trip took only 6 hours because the speed was 3 miles per hour faster. What was the consultant's speed each way?
Hi,
Let r represent the speed to the meeting, (r+3) speed returning
d = r*t distances are the same to and from meeting
r*7hr = (r+3)*6hr
solving for r
r*7hr = r*6hr +18
r*7hr - r*6hr = 18
r = 18mph, speed to the meeting. 21mph speed returning