SOLUTION: Liz commutes 30 mi. to her job each day. She Finds that if she drives 10 mi/h faster it takes her 6 minutes less to get to work. Find her new speed. I tried setting this problem

Algebra.Com
Question 370575: Liz commutes 30 mi. to her job each day. She Finds that if she drives 10 mi/h faster it takes her 6 minutes less to get to work. Find her new speed.
I tried setting this problem up on a chart. For some reason when I worked the problem out I came out with really odd fractions, and I am not quite sure what I have done wrong. Any kind of help would truly mean a lot to me.

Found 2 solutions by ewatrrr, jim_thompson5910:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let r represent her old speed
d = r*t
30 = r*t
30/r = t


Multiplying thru by 10r(r+10) so as all denominators = 1
300r = 300(r+10) - r(r+10)
300r = 300r + 3000 - r^ - 10r
r^2 + 10r - 3000 = 0
factor
(x + 60)(x-50) = 0
x + 60)= 0 x = -60 cannot use
(x-50) = 0 x = 50mph her old speed. Her new speed would be 60mph( 10mph faster)
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let r = original speed.

and let t = time to get to work driving that original speed.


So if "Liz commutes 30 mi. to her job each day", this means that because we're using the formula where the distance is


So the first equation is


In addition, because "she drives 10 mi/h faster it takes her 6 minutes less to get to work", we can say that

Notes: since she drives 10 mph faster, her new speed is r+10. Also, because 60 min = 1 hour, this means that 6 min = hours. So if it takes 6 mins or or an hour less, then the new time is


So the second equation is


-----------------------------------------------------------

Now let's use both equations to solve for t and r


Start with the first equation.


Divide both sides by t to isolate r.


Flip the equation.


Move onto the second equation.


Plug in


Multiply 10 by


Combine the fractions.


Distribute


Multiply.


Note: the 't' terms cancel in the first fraction while in the second, we're dividing each term by 10.


Multiply EVERY term by the LCD 't' to clear out the fractions.


Distribute.


Subtract 30t from both sides.


Combine like terms.



Notice that the quadratic is in the form of where , , and


Let's use the quadratic formula to solve for "t":


Start with the quadratic formula


Plug in , , and


Negate to get .


Square to get .


Multiply to get


Rewrite as


Add to to get


Multiply and to get .


Take the square root of to get .


or Break up the expression.


or Combine like terms.


or Simplify.


So the possible solutions are or


However, since a negative time isn't possible, this means that the only solution for 't' is


Remember that 't' is the time in hours. So convert to minutes to get minutes


So the time it takes to travel 30 miles at the original speed is 36 minutes.


Recall that we made . So plug into the equation to get


So her original speed is 50 mph. Add 10 mph to this speed to get 50+10 = 60 mph


So her new speed is 60 mph.


I'll leave the check to you. Remember to use the formula


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim

RELATED QUESTIONS

Liz commutes 30 mi. to her job each day. She finds that if she drives 10 mi/h faster it... (answered by mananth)
Jacqui commutes 30 mi to her job each day. She finds that if she drives 10 mi/h faster,... (answered by ankor@dixie-net.com)
Jacqui commutes 30 mi to her job each day. She finds that if she drives 10 mi/h faster,... (answered by ankor@dixie-net.com)
jacqui commutes 30 miles to her job each day. She finds that if she drives 10 miles/hour (answered by richwmiller,stanbon)
Jacqui commutes 30 mi to her job each day.She finds that if she drives 10mi/faster, it... (answered by josgarithmetic,MathTherapy,rothauserc)
Nancy drives 20 miles to her school each day. If she drives 10 miles per hour faster, it... (answered by richwmiller)
Jana can jog 5 miles downhill in the same time that it takes her to jog 3 miles uphill.... (answered by mananth)
Kerry commutes 60 mi per day. If she drives 30 mi/h during the morning rush and returns... (answered by stanbon)
The time "t" that it takes Hannah to bike to school varies inversely as her average... (answered by ankor@dixie-net.com,josgarithmetic)