SOLUTION: Two trucks leave a warehouse at the same time, traveling in opposite directions. The rate of the faster truck exceeds that of the slower truck by 5 miles per hour. After 5 hours th
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Question 362228: Two trucks leave a warehouse at the same time, traveling in opposite directions. The rate of the faster truck exceeds that of the slower truck by 5 miles per hour. After 5 hours they are 600 miles apart. What are the rates of the trucks?
Answer by HasanSahin(52) (Show Source): You can put this solution on YOUR website!
If they have constant velocities in the initial condition:
Let's say v1 = speed of faster truck and v2 = speed of slower truck..
The distance they travel in a certain time is X = V*t where t is the time.
Let's say x1 = distance of faster truck from warehouse and x2 = distance of slower truck from warehouse..
So that >> x1 = v1*t and x2 = v2*t
Total distance after 5 hours is
x1 + x2 = v1*5 + v2*5 = 600 miles (1)
We know that v1 = v2 + 5 (2)
And therefore, put v1 in the (2)nd equation into the (1)st equation such that;
(v2 + 5)*5 + v2*5 = 600 >>
5*v2 + 25 + 5*v2 = 600 >>
10*v2 = 575 miles >>
v2 = 57.5 miles per hour and if you put v2 into any equation you'll get >>
v1 = 62.5 miles per hour
RF.
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