SOLUTION: Two cars are moving in the same direction pass a point on the road at the same time. Car A is moving with a constant velocity of 15m/s. Car B has a velocity of 5m/s at that instant

Question 361765: Two cars are moving in the same direction pass a point on the road at the same time. Car A is moving with a constant velocity of 15m/s. Car B has a velocity of 5m/s at that instant and is accelerating at the rate of 1m/s^2.
Useing the formula s=ut+1/2at^2 where s is the distance from the starting point in metres, u is the velocity initially, a is acceleration in m/s^2 and t is the time in seconds. write a relationship between s and t for car A and car B.
Please help!
Answer by HasanSahin(52) (Show Source): You can put this solution on YOUR website!
The relationship is basically like this:
Let's say the time passed for a certain time: "t"
The car from A point will travel a distance = x1 = 15*t
The car from B point will travel a distance = x2 = 5*t + (1/2)*1*(t^2)
u*t is the distance gained by initial velocity and (1/2)*a*t^2 is the distance gained by acceleration.

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