SOLUTION: A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally.

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Let the width be x ft.
The length is x+50 ft.
The length of the diagonal is sqrt [(x^2) + (x+50)^2] ft;
[(x^2) + (x+50)^2] = 250^2
=> x^2 + (x+50)^2 = 62500
=> x^2 + x^2 + 100x + 2500 = 62500
=> x^2 + 50x - 30000 = 0
=> x = [-50 + sqrt(2500+120000)]/2 because x cannot be negative
=> x = [-50 + sqrt(122500)]/2
=> x = (-50+350)/2 = 150;
The Dimension of the parking lot is 200 ft X 150 ft