# SOLUTION: Jim and John drive from point A to point B separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant speed

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 Question 360345: Jim and John drive from point A to point B separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant speeds. Find when John catches up with Jim.Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!Jim and John drive from point A to point B separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant speeds. Find when John catches up with Jim. -------------- m = Jim's speed n = John's speed --------- d = rt To go the total distance: d = m*10 --> m = d/10 d = n*5 --> n = d/5 ------- Jim starts at 0600, t = 0 At some time t: m*t = n*(t-4) (d/10)t = (d/5)*(t-4) d cancels t/10 = (t-4)/5 t = 2(t-4) t = 2t - 8 t = 8 hours 0600 + 8 = 1400 or 2 PM ----------------- Interesting problem. ------------------- Another approach: John's speed is 2x Jim's speed. Since John arrived 1 hour before Jim going 2x as fast, John covered the same distance in his last hour that Jim covered in 2 hours. --> They were at the same point 1 hour before John's arrival and 2 hours before Jim's arrival. --> 3PM - 1 hour = 4PM - 2 hours = 2PM