SOLUTION: I can't remember how to do these? I know it's rate times time = distance, but I come up with 54mph, is this right? A twin-engined aircraft can fly 648 miles from city A to B in

Question 360260: I can't remember how to do these? I know it's rate times time = distance, but I come up with 54mph, is this right?
A twin-engined aircraft can fly 648 miles from city A to B in 3 hours with the wind and make the return trip in 6 hours against the wind. What is the speed of the wind?
Found 2 solutions by robertb, mananth:
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
let p = speed of the wind in still air, w = speed of the wind.
Then .
after dividing by 3 and 6, respectively,
Adding corresponding sides of the equations, we get
2p = 324,
p = 162, and w = 216-162 = 54.
The plane goes 162 mph, the wind 54 mph.

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
A twin-engined aircraft can fly 648 miles from city A to B in 3 hours with the wind and make the return trip in 6 hours against the wind. What is the speed of the wind?
...
distance = 648
time = 3 hours
speed with wind = 648/3 = 216 mph
speed of wind = x
...
against wind speed = 648/6 = 108 mph
,..
216-x=x+108
216-108=2x
108=2x
x= 58 mph wind rate
...
m.ananth@hotmail.ca
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