SOLUTION: Scott noted that the fast freight train left at noon and arrived there at 6 p.m. The next day he realized that the slow freight had made the same trip in 8 hours. What was the spee

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Question 357606: Scott noted that the fast freight train left at noon and arrived there at 6 p.m. The next day he realized that the slow freight had made the same trip in 8 hours. What was the speed of the slow freight if the speed of the fast freight was 60 miles per hour?
Answer by neatmath(302) About Me  (Show Source):
You can put this solution on YOUR website!
To solve this problem, we will use the formula distance=rate*time or

d=rt

For the fast train, we know that

d=60%2A6 fast train

d=360 miles

Since the two distances traveled by the two trains are equal, we now know

360=r%2A8 slow train

r=45

Thus, the slow freight train traveled at 45 miles per hour.

I hope this helps!