SOLUTION: Butch starts walking from point A at 2 miles per hour. One-half hour later, Dick starts walking from point A at 3.5 miles per hour and follows the same route. How long will it take

Question 356578: Butch starts walking from point A at 2 miles per hour. One-half hour later, Dick starts walking from point A at 3.5 miles per hour and follows the same route. How long will it take Dick to catch up with Butch?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Butch starts walking from point A at 2 miles per hour. One-half hour later, Dick starts walking from point A at 3.5 miles per hour and follows the same route. How long will it take Dick to catch up with Butch?
..
speed of Butch = 2 mph
speed of Dick = 3.5 mph.
Dick gains 3.5 -2 = 1.5 mph.
..
Butch starts 1 1/2 hour early.
so he has traveled 3/2 * 2 = 3 miles when Dick starts.
..
dick gains 1.5 mph
..
time = distance / speed
3/1.5 = 2 hours to catch up
...
m.ananth@hotmail.ca
RELATED QUESTIONS
Andy starts walking from point a at 2 miles per hour. One-half hour later, Aaron starts... (answered by ankor@dixie-net.com)

at 10 a.m., emma begins walking on a path at a rate of 3 miles per hour. one hour later... (answered by Boreal)

Teri begins walking east at 2 miles per hour at 1:00 PM. If Cindy leaves from the same... (answered by addingup,advanced_Learner,MathTherapy)

I think I am doing something wrong maybe someone can tell me what Did wrong. The... (answered by stanbon)

3. Maybank Malaysia is sponsoring a walking race. Ali and Abu love to join the... (answered by ikleyn)

A mother horse and a baby horse walk 10 miles from point A to point B. The mother�s speed (answered by ankor@dixie-net.com,onlinepsa)

A starts walking along the road at 3 mi/hr.Two hours later B starts at the same direction (answered by rfer)

Having problem figuring out this one. any help will be appreciated. Myron corporation is (answered by ankor@dixie-net.com)

Hello, I have this word problem that i could use some help on. Jeff starts driving... (answered by Paul)