SOLUTION: A slow train travelling at 25 km/h leaves a station 1/2 h before another train travelling at 40 km/h. If the trains travel in the same direction on parallel routes, when does the

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Question 351889: A slow train travelling at 25 km/h leaves a station 1/2 h before another train travelling at 40 km/h. If the trains travel in the same direction on parallel routes, when does the faster train pass the slower train? What would x represent and what would y represent?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A slow train traveling at 25 km/h leaves a station 1/2 h before another train traveling at 40 km/h. If the trains travel in the same direction on parallel routes, when does the faster train pass the slower train? What would x represent and what would y represent?
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Faster train DATA:
rate = 40 km/h ; time = x-1/2 hrs ; distance = 40(x-(1/2)) = 40x-20 km
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Slower train DATA:
rate = 25 km/h ; time = x hrs ; distance = 25x km
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Equation:
distance = distance
40x-20 = 25x
Subtract 25x from both sides.
Add 20 to both sides.
15x = 20
x = 4/3 hour = 80 minutes (time for the slower train)
x-(1/2) = 4/3-(1/2) = (8-3)/6 = 5/6 = 50 minutes (time for the faster train)
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Cheers,
Stan H.
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