SOLUTION: While following a circular path of radius 8.0 m a truck requires a centripetal acceleration of 2.0 m/s^2. What is the period and speed?
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Question 350553: While following a circular path of radius 8.0 m a truck requires a centripetal acceleration of 2.0 m/s^2. What is the period and speed?
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
The centripetal force is
Fcp = m*v^2/r
and since F = m*a ---> a = F/m = mv^2/(r*m)-->
a = v^2/r (a = centripetal acceleration)
plug in your numbers:
2 m/sec^2 = v^2/8 m
v^2 = 16 m^2/sec^2
v = 4 m/sec
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