SOLUTION: A man commutes to work a distance 35 miles and returns on the same route at the end of the day. His average rate on the return trip is 20 miles per hour faster than his average rat

Question 350519: A man commutes to work a distance 35 miles and returns on the same route at the end of the day. His average rate on the return trip is 20 miles per hour faster than his average rate on the outgoing trip. write the total time, T, in hours, devoted to his out going and return trips as a function of his rate on the outgoing trip, x. Then find an interpret T(25)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A man commutes to work a distance 35 miles and returns on the same route at the end of the day.
His average rate on the return trip is 20 miles per hour faster than his average
rate on the outgoing trip.
write the total time, T, in hours, devoted to his out going and return trips as a
function of his rate on the outgoing trip, x.
:
x = speed on the outgoing trip
then
(x+20) = speed on the return trip
:
Write a time equation, time = dist/speed
:
T(x) = +
:
Then find an interpret T(25)
T(25) = +
T(25) = +
T(25) = 1.4 + .78
T(25) = 2.18 hrs total driving time
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