SOLUTION: Kesha drove from Buffalo to Syracuse at an average rate of 48 miles per hour. On the return trip along the same road she was able to travel at an average rate of 60 miles per hour.

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Question 350283: Kesha drove from Buffalo to Syracuse at an average rate of 48 miles per hour. On the return trip along the same road she was able to travel at an average rate of 60 miles per hour. The trip from Buffalo to Syracuse took one-half hour longer than the return trip. How long did the return trip take?
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Kesha drove from Buffalo to Syracuse at an average rate of 48 miles per hour.
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B to S DATA:
rate = 48 mph ; time = x hrs ; distance = 48x miles
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On the return trip along the same road she was able to travel at an average rate of 60 miles per hour. The trip from Buffalo to Syracuse took one-half hour longer than the return trip.
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S to B DATA:
rate = 60 mph ; time = x-(1/2) hrs ; distance = 60(x-(1/2)) = 60x-30 miles
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How long did the return trip take?
Equation:
distance = distance
48x = 60x-30
12x = 30
x = 5/2 hrs
x-(1/2) = 5 hrs (time for return trip)
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Cheers,
Stan H.
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