SOLUTION: A boater travels 16 miles per hour on the water on a still day. During one particular windy day, he finds that he travels 48 miles with the wind behind him in the same amount of t

Question 349757: A boater travels 16 miles per hour on the water on a still day. During one particular windy day, he finds that he travels 48 miles with the wind behind him in the same amount of time that he travels 16 miles into the wind. find the rate of wind.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=RT
48=(16+W)T
T=48/(16+W)
16=(16-W)T
T=16/(16-W)
48/(16+W)=16/(16-W) CROSS MULTIPLY.
16(16+W)=48(16-W)
256+16W=768-48W
16W+48W=768-256
64W=512
W=512/64
W=8 MPH. IS THE RATE OF THE WIND.
PROOF:
48/(16+8)=16/(16-8)
48/24=16/8
2=2
RELATED QUESTIONS
A boater travels 16 miles per hour on the water on a still day. During one particular... (answered by jorel1380)

a boater travels 16 miles per hour on the water on a still day. During one particular... (answered by Alan3354)

a clclist rides 16 miles per hour on level ground on a still day. He finds that he finds... (answered by mbarugel)

Jim can run 5 miles per hour on level ground on a still day. One windy day, he runs 10... (answered by Paul)

Jim can run 5 miles per hour on a level ground on a still day. One windy day, he runs 11... (answered by scott8148,mananth)

Solve the problem and show the work. Jim can run 5 miles per hour on level ground on a... (answered by ptaylor)

Solve the problem. Jan can run 5 miles per hour on level ground on a still day. One... (answered by checkley71)

jim can run 5 miles per hour on level ground on a still day. One windy day, he runs 10... (answered by Paul)

HELP!!! I have worked this problem and can't get it. Problem: Jim can run 5 miles... (answered by fractalier,mbarugel,AnlytcPhil)