SOLUTION: Mike & Bill row their boat (constant speed) 55mi downstream for 2.5hrs, helped by the current. Rowing at the same rate, the trip back against the current takes 5.5hrs. Find the rat
Algebra.Com
Question 347047: Mike & Bill row their boat (constant speed) 55mi downstream for 2.5hrs, helped by the current. Rowing at the same rate, the trip back against the current takes 5.5hrs. Find the rate of the current.
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
Let R=rate of boat in still water
and let r=rate of current
(DOWNSTREAM WE ADD THE RATE OF THE CURRENT; UPSTREAM, WE SUBTRACT)
Downstream:
R+r=55/(2.5)=22-------------------eq1
Upstream:
R-r=55/(5.5)=10------------------eq2
add eq1 and eq2:
2R=32
R=16 mph---speed of boat ---substitute into eq1 and we get:
r=22-16=6 mph---speed of current
CK
2.5*22=55
5.5*10=55
Hope this helps--ptaylor
RELATED QUESTIONS
Can you help me please? This application problem I can't figure out.
Julie and Eric... (answered by uma)
Julie and Eric row their boat( at a constant speed) 45 miles downstream for 5 hours,... (answered by Mathtut)
Julie and Eric row their boat (at a constant speed) 45 miles downstream for 5 hours,... (answered by josmiceli)
Julie and Eric row their boat (at a constant speed) 45 miles downstream for 5 hours,... (answered by nerdybill,MathTherapy)
Julie and Eric row their boat (at a constant speed) 32 miles downstream for 4 hours,... (answered by TimothyLamb)
Julie and Eric row their boat( at a constant speed) 63 miles downstream for 7 hours,... (answered by lwsshak3)
Julie and Eric row their boat (at constant speed ) 40 miles downstream for 4 hours,... (answered by josgarithmetic,MathTherapy)
Julie and Eric row their boat (at a constant speed) 63 miles downstream for 7 hours,... (answered by ikleyn)