SOLUTION: Students are traveling in two cars to a football game 135 miles away. The first car leaves on time and travels at an average speed of 45 miles per hour. The second car starts

Question 345253: Students are traveling in two cars to a football game 135 miles away. The first
car leaves on time and travels at an average speed of 45 miles per hour. The
second car starts 1/2 hour later and travels at ab average speed of 55 miles per
hour. How long will it take the second car to catch up to the first car? Will
the second car catch up to the first car before it arrives at the game?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=RT
135=45T FIRST CAR.
135=55(T-.5) SECOND CAR.
45T=55(T-.5
45T=55T-27.5
45T-55T=-27.5
10T=-27.5
T=27.5/10
T=2.75 HOURS FOR THE TRIP TIME
45*2.75=123.75 MILES IS THE POINT WHERE THEY MEET.
55(2.75-.5)=55*2.25=123.75 DITTO.
2.75-.5=2.25 HOURS THE SECOND CAR WILL CATH UP WITH THE FIRST CAR.
yes THEY WILL MEET BEFORE THEY ARRIVE @ THE FOOTBALL GAME.
123.75 MILES IS LESS THAN 135 MILES.
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