SOLUTION: Larry starts cycling at 20 mi/hr. One hour later, Rebecca starts cycling from the same place at 25 mi/hr, going in the same direction on the same road as Larry. How long will it ta
Algebra.Com
Question 343639: Larry starts cycling at 20 mi/hr. One hour later, Rebecca starts cycling from the same place at 25 mi/hr, going in the same direction on the same road as Larry. How long will it take Rebecca to catch up to Larry?
*Someone told me to do
20T = 25(T-1)
20T = 25T - 25
20T - 25T = -25
-5T = -25
T = -25/-5
T = 5 hours.
I am not sure if this is right? If it is right, I don't understand what everything stands for or the formula used. I need an explanation please.
Found 2 solutions by ankor@dixie-net.com, scott8148:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Larry starts cycling at 20 mi/hr. One hour later, Rebecca starts cycling from the same place at 25 mi/hr, going in the same direction on the same road as Larry. How long will it take Rebecca to catch up to Larry?
:
This is right, this equation makes use of the fact that when R catch L then
they will have traveled the same distance.
Dist = speed * time
:
T = L's travel time. (dist = 20T)
R started 1 hour later so
(T-1) = R's travel time. dist = (25(t-1))
:
With this in mind, the equation is:
L's dist = R's dist
20T = 25(T-1)
20T = 25T - 25
20T - 25T = -25
-5T = -25
T = -25/-5
T = 5 hours.
YOu solved for T correctly, you can prove this by finding the dist each has
traveled, they should be equal
L's dist: 20*5 = 100 mi
R's dist: 25(5-1) = 100 mi also
:
:
Did this shed some light on this kind of problem, any questions? use the comment feature.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
Rebecca catches Larry when they have both traveled the same distance
distance equals rate multiplied by time
Rebecca's rate is 25 mph and her time is one hr less than Larry's
Larry's rate is 20 mph
the T in the equations represents Larry's time
depending on your viewpoint, you might say that Rebecca's time to catch Larry doesn't start until Rebecca starts
___ so the answer is either 4 hr or 5 hr
hope this helps
RELATED QUESTIONS
Need help for the following sum:
A starts walking north from Point X at 7 a.m. with a... (answered by mananth)
Two friends living 39 mi apart,leave their homes at the same time on bicycles and travel... (answered by stanbon)
At 9:30 a.m. Andrew left Exeter for Portsmouth, cycling at 12 mi/hr. At 10:00 a.m. Stacy... (answered by solver91311)
From Abu Dhabi to Al-Ain is 149 km. A cyclist starts from Abu Dhabi cycling to Al-Ain at... (answered by josmiceli,stanbon)
Please help solve this problem. This question is from a teacher created worksheet.
Two... (answered by ptaylor)
A bus leaves LA traveling at 50 mi/hr. An hour later a car traveling on the same road... (answered by josgarithmetic)
A runner starts at the beginning of a runners’ path and runs at a
constant rate of 5... (answered by josmiceli)
Two cars start from the same point. One travels south at 75 mi/hr and the other travels... (answered by richwmiller)
2. grace starts jogging home at 5 km/hr. will leaves 10 minutes later on a bike (from the (answered by Alan3354,stanbon)