You can put this solution on YOUR website!
I began to count seconds. It took me 9 seconds to get to the post.
When I reached the pole, I looked up to see that she was just passing a mango tree.
I again counted seconds until I reahed the mango tree and it took me 11 seconds.
When I reached the fire hydrant, she was passing a phonebooth.
It took me 14 seconds to each the phonebooth.
I knew that I walked 2 paces in 1 second and my pace was 1 yard long.
Approximately how fast in miles per hour was the jogger moving?
Find the speed of the observer, 2yd per sec, 6 ft/sec
= 4.091 mph hr
I think we can find the jogger speed using the time and distances to the pole
and to the mango tree.
Distance to pole: 6 * 9 = 54 ft
Distance to Mango tree: 6 * 11 = 66 ft
We can see the observer traveled 54 ft while the jogger traveled 66 ft
Let j = speed of the jogger
write a ratio equation, find the speed in mph
54j = 4.091 * 66
54j = 270
j = 5 mph is the jogger speed
Let me know if I screwed this one up.