SOLUTION: Mike and Adam left a bus
terminal at the same time and
traveled in opposite directions.
Mike's bus was in heavy traffic
and had to travel 20 mph slower
than Adam's bus.
Algebra.Com
Question 337939: Mike and Adam left a bus
terminal at the same time and
traveled in opposite directions.
Mike's bus was in heavy traffic
and had to travel 20 mph slower
than Adam's bus. After 3 hours,
their buses were 270 miles apart.
How fast was each bus going?
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
270/3=90 mph for one hr
x+x-20=90
2x=110
x=55 mph
x-20=35 mph
RELATED QUESTIONS
Mike and Adam left a bus terminal at the same time and traveled in opposite directions. (answered by josmiceli)
Mike and Adam left a bus terminal at the same time and traveled in opposite directions.... (answered by checkley75)
mike and adam left a bus terminal at the same time and traveled in opposite directions.... (answered by mananth,stanbon)
mike and adam left a bus terminal at the same time and traveled in opposite directions.... (answered by jorel1380)
Mike and Adam left a bus terminal at the same time and traveled in opposite directions.... (answered by solver91311)
I have a math problem and the answer but need help with the setup and solving it.
Mike (answered by Tatiana_Stebko)
mike and adam left a bus terminal at the same time and traveled in opposite direcrtions.... (answered by prince_abubu)
Mike and Adam left a bus terminal at the same time and traveled in opposite directions.... (answered by josmiceli)
"Mike and Adam left a bus terminal at the same time and traveled in opposite directions. (answered by richwmiller)