SOLUTION: An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic
Algebra.Com
Question 333448: An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h = -16t^2 + 48t + 160. When will the object hit the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h = -16t^2 + 48t + 160. When will the object hit the ground?
------------
When h = 0
h = -16t^2 + 48t + 160 = 0
Solve for t
RELATED QUESTIONS
An object is thrown upward from the top of a 160 foot building with an initial velocity... (answered by mananth)
An object is thrown upward from the top of a 160-foot building with an initial... (answered by ankor@dixie-net.com)
Hello I really need some assistance with the following algebra word problem:
"An... (answered by josmiceli)
Please help me! I think that the answer is 5 seconds, but I don't know. Please show... (answered by Alan3354)
an object is thrown upward from the top of a 48-foot building with an initial velocity of (answered by rothauserc)
An Object is thrown upward from the top of a 48-foot building with an initial velocity of (answered by Alan3354,Boreal)
an object is thrown upward from the top of a 64 foot building with an initial velocity of (answered by ikleyn)
An object is thrown upward from the top of a 260 foot tall building with an initial... (answered by solver91311)
An object is thrown upward from the top of a 96 foot building with an initial velocity of (answered by josmiceli)