SOLUTION: The braking distance (in feet) of a car going V mph is given by {{{d(v)=v^2/20+v}}} v is greater or equal to 0. how fast would the car have been traveling for a braking distance

Question 332220: The braking distance (in feet) of a car going V mph is given by v is greater or equal to 0.
how fast would the car have been traveling for a braking distance of 150feet? round to nearest mile per hour.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The braking distance (in feet) of a car going V mph is given by
v is greater or equal to 0.
how fast would the car have been traveling for a braking distance of 150feet?
round to nearest mile per hour.
:
Write it:
= 150
multiply by 20, results
v^2 + 20v = 20(150)
:
v^2 + 20v = 3000
:
v^2 + 20v - 3000 = 0
Solve for v using the quadratic formula

in this equation; x=v; a=1; b=20; c= -3000

Two solutions, we only want the positive solution

v =
v = 45.68 mph for a stopping distance of 150 ft
:
:
See if that flies in the original equation

d(v) = 150.00, confirms our solution
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