SOLUTION: if each of base angles of an isoceles triangle is 5 less than twice the vertix angle. find the number of each angle?
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Question 330069: if each of base angles of an isoceles triangle is 5 less than twice the vertix angle. find the number of each angle?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let vertex angle = x
the base angles will be 2x-5
..
2x-5+2x-5+x = 180 ( sum of all angles = 180 deg)
5x-10=180
5x=180+10
5x=190
x=190/5
x= 38 vertex
2x-5 is the base angle = 2*38-5
=76-5
=71 deg.
The angles are 38,71,71
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