SOLUTION: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10mph and starts 3 hours after the first cyclist who is traveling at 6 mph. How much tim

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Question 327420: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10mph and starts 3 hours after the first cyclist who is traveling at 6 mph. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer by Fombitz(32388) About Me  (Show Source):
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Rate*Time=Distance
.
.
.
R1=6
R2=10
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.
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With the 3 hour head start, Cyclist 1 is 18 miles ahead of Cyclist 2.
t is measured from the time Cyclist 2 starts.
D1=18%2B6t
D2=10t
,
,
,
Find t when D1=D2.
18%2B6t=10t
4t=18
t=9%2F2 or 4.5 hrs