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John and Tony start from the same place at the same time and head for a town 10 miles away.
John walks twice as fast as Tony and arrives 3 hours before Tony. Find the speed of each.
Let s = Tony's walking speed
2s = John's walking speed
Write a time equation: Time = dist/speed
John's time + 3 hrs = Tony's time
+ 3 =
multiply by 2s, results:
10 + 2s(3) = 2(10)
10 + 6s = 20
6s = 20 - 10
6s = 10
s = 1
mph is Tony's speed
) = 3
is John's speed
Check solution with a calc by finding the times
10/1.67 ~ 6 hrs
10/3.33 ~ 3 hrs; a 3 hr difference