SOLUTION: John and Tony start from the same place at the same time and head for a town 10 miles away. John walks twice as fast as Tony and arrives 3 hours before Tony. Find the speed of each

Question 322988: John and Tony start from the same place at the same time and head for a town 10 miles away. John walks twice as fast as Tony and arrives 3 hours before Tony. Find the speed of each.

Found 2 solutions by solver91311, ankor@dixie-net.com:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Let represent the time in hours it takes the faster guy to go 10 miles. Then it takes hours for the slower guy to make the same trip. Let represent the slower speed. Then the faster speed is

Using

or

Since 10 equals 10,

Therefore:

mph.

for the slow guy -- twice that for the fast guy.

John

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
John and Tony start from the same place at the same time and head for a town 10 miles away.
John walks twice as fast as Tony and arrives 3 hours before Tony. Find the speed of each.
:
Let s = Tony's walking speed
then
2s = John's walking speed
:
Write a time equation: Time = dist/speed
:
John's time + 3 hrs = Tony's time
+ 3 =
multiply by 2s, results:
10 + 2s(3) = 2(10)
10 + 6s = 20
6s = 20 - 10
6s = 10
s =
s = 1 mph is Tony's speed
then
2(1) = 3 is John's speed
:
:
Check solution with a calc by finding the times
10/1.67 ~ 6 hrs
10/3.33 ~ 3 hrs; a 3 hr difference
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