# SOLUTION: A ball is thrown upward with an initial velocity of 32 ft/sec from a height of six feet. The function s(t)=-16t^2+32t+6 gives the height of the ball t seconds after release. Determ

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: A ball is thrown upward with an initial velocity of 32 ft/sec from a height of six feet. The function s(t)=-16t^2+32t+6 gives the height of the ball t seconds after release. Determ      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Travel and Distance Solvers Lessons Answers archive Quiz In Depth

 Question 316048: A ball is thrown upward with an initial velocity of 32 ft/sec from a height of six feet. The function s(t)=-16t^2+32t+6 gives the height of the ball t seconds after release. Determine the time when the ball is at maximun height, and find that height.Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!s(t) is a downward opening parabola ("a" is negative) ; so the maximum is at the vertex , which is on the axis of symmetry t = -b / 2a = -32 / 2(-16) = 1 s(1) = -16(1^2) + 32(1) + 6 = 22