SOLUTION: A bicycle leaves town at 10mph at 8am and a car leaves at 11am, traveling in the same direction at 50mph. How many minutes after 11am will it be when the car overtakes the bike?

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Question 315240: A bicycle leaves town at 10mph at 8am and a car leaves at 11am, traveling in the same direction at 50mph. How many minutes after 11am will it be when the car overtakes the bike?
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
D=RT
D=10T FOR THE CYCLIST
D=50(T-3)
10T=50(T-3)
10T=50T-150
10T-50T=-150
-40T=-150
T=-150/-40
T=3.75 HOURS AFTER 8 AM THEY WILL MEET.
8:00+3:45=11:45 OR 11:45 THE CAR WILL OVERTAKE THE CYCLIST.

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