SOLUTION: A water rocket is launched upward with an initial velocity of 48 ft/sec. It's height h, in feet, after t seconds is given by h=48t - 16t^2. After how many seconds will the height o

Question 315040: A water rocket is launched upward with an initial velocity of 48 ft/sec. It's height h, in feet, after t seconds is given by h=48t - 16t^2. After how many seconds will the height of the rocket be 20 feet?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

Factor the quadratic.

Two solutions:

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The rocket first reaches 20 ft in 1/2 sec going up and then reaches 20 ft in 5/2 sec going down.
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